150x-(3100+7x+0.1x^2)=0

Solution for 150x-(3100+7x+0.1x^2)=0 equation:

150x-(3100+7x+0.1x^2)=0

We get rid of parentheses

-0.1x^2-7x+150x-3100=0

We add all the numbers together, and all the variables

-0.1x^2+143x-3100=0

a = -0.1; b = 143; c = -3100;
Δ = b2-4ac
Δ = 1432-4·(-0.1)·(-3100)
Δ = 19209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(143)-\sqrt{19209}}{2*-0.1}=\frac{-143-\sqrt{19209}}{-0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(143)+\sqrt{19209}}{2*-0.1}=\frac{-143+\sqrt{19209}}{-0.2}
$